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(Oops! I've just noticed that the first message in the thread was sent to<br>
<a class="moz-txt-link-abbreviated" href="mailto:vtkusers@public.kitware.com">vtkusers@public.kitware.com</a> - I hope it's the same list.)<br>
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<blockquote type="cite"> were the triangles restricted to two dimensions?
I suspect that if you <br>
define a triangle via 6 values (as opposed to 9) then it will lie on <br>
the surface... </blockquote>
Thanks for the message, Tom. I've also thought of this - but we really need
<br>
to work with three-dimensional surfaces. <br>
<br>
In this case, it seems that the only available solution is to implement my
own algorithm. <br>
This task is somehow made easy by the fact that, if the vectors defined in
the points of <br>
a cell are <i>parallel </i>to the cell plane, then the streamline that starts
in that cell lies <br>
entirely inside the cell. See the first attached image. <br>
<br>
However, I do not know how to persuade the integration process to end at
the <br>
border of the cell. See the second attached image: The end of the streamline
<br>
is close to an edge, but <i>not quite</i> on the edge. Since it does not
touch, I cannot get <br>
(easily) a point on that edge, which should be the seed point for the <br>
streamline on the adjacent face... <br>
<br>
Petru <br>
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