The function is simple:<br><br>z = Zmax * Sin ((12.4 * x) / Nx ) + (4 * y) / Ny<br><br>Mesh Nx * Ny ; 0< x <= Nx and 0< y <= Ny<br>x and y integers<br><br>Hugo<br><br><div class="gmail_quote">2010/9/29 David Doria <span dir="ltr"><<a href="mailto:daviddoria@gmail.com">daviddoria@gmail.com</a>></span><br>
<blockquote class="gmail_quote" style="margin: 0pt 0pt 0pt 0.8ex; border-left: 1px solid rgb(204, 204, 204); padding-left: 1ex;"><div class="gmail_quote"><div class="im">On Wed, Sep 29, 2010 at 12:57 PM, Hugo Valdebenito <span dir="ltr"><<a href="mailto:hugo@maptek.cl" target="_blank">hugo@maptek.cl</a>></span> wrote:<br>
<blockquote class="gmail_quote" style="margin: 0pt 0pt 0pt 0.8ex; border-left: 1px solid rgb(204, 204, 204); padding-left: 1ex;">Hi David<br><br>Thanks for you reply, I'm trying to make a 3D triangulation using a surface function (depend of X and Y) using a regular mesh for x and y, my idea is to generate big amount of points (or triangles) and generate a triangulation. I'm comparing VTK with Open Inventor engine. <br>
<br>Hugo<br><br></blockquote><div><br></div></div><div>This may be what you're looking for: </div><a href="http://www.vtk.org/Wiki/VTK/Examples/Cxx/Filters/TriangulateTerrainMap" target="_blank">http://www.vtk.org/Wiki/VTK/Examples/Cxx/Filters/TriangulateTerrainMap</a></div>
<div class="gmail_quote"><br><div>vtkDelaunay2D projects the points on to the XY plane before performing the triangulation, so you can give it your points (which are a function of x and y) and it will produce a nice result.</div>
<div><br></div><font color="#888888"><div>David </div></font></div>
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